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40 File Name: 15.8.2.15.js
41 ECMA Section: 15.8.2.15 Math.round(x)
42 Description: return the greatest number value that is closest to the
43 argument and is an integer. if two integers are equally
44 close to the argument. then the result is the number value
45 that is closer to Infinity. if the argument is an integer,
48 - if x is NaN return NaN
51 - if x = Infinity return Infinity
52 - if x = -Infinity return -Infinity
53 - if 0 < x < 0.5 return 0
54 - if -0.5 <= x < 0 return -0
56 Math.round( 3.5 ) == 4
57 Math.round( -3.5 ) == 3
59 - Math.round(x) == Math.floor( x + 0.5 )
60 except if x = -0. in that case, Math.round(x) = -0
62 and Math.floor( x+0.5 ) = +0
65 Author: christine@netscape.com
69 var SECTION = "15.8.2.15";
70 var VERSION = "ECMA_1";
72 var TITLE = "Math.round(x)";
73 var BUGNUMBER="331411";
77 writeHeaderToLog( SECTION + " "+ TITLE);
79 new TestCase( SECTION,
84 new TestCase( SECTION,
89 new TestCase( SECTION,
94 new TestCase( SECTION,
99 new TestCase( SECTION,
104 new TestCase( SECTION,
109 new TestCase( SECTION,
110 "Math.round('.99999')",
112 Math.round('.99999') );
114 new TestCase( SECTION,
115 "Math.round('12345e-2')",
117 Math.round('12345e-2') );
119 new TestCase( SECTION,
122 Math.round(Number.NaN) );
124 new TestCase( SECTION,
129 new TestCase( SECTION,
134 new TestCase( SECTION,
135 "Infinity/Math.round(-0)",
137 Infinity/Math.round(-0) );
139 new TestCase( SECTION,
140 "Math.round(Infinity)",
141 Number.POSITIVE_INFINITY,
142 Math.round(Number.POSITIVE_INFINITY));
144 new TestCase( SECTION,
145 "Math.round(-Infinity)",
146 Number.NEGATIVE_INFINITY,
147 Math.round(Number.NEGATIVE_INFINITY));
149 new TestCase( SECTION,
154 new TestCase( SECTION,
159 new TestCase( SECTION,
164 new TestCase( SECTION,
169 new TestCase( SECTION,
174 new TestCase( SECTION,
175 "Infinity/Math.round(-0.49)",
177 Infinity/Math.round(-0.49));
179 new TestCase( SECTION,
180 "Infinity/Math.round(-0.5)",
182 Infinity/Math.round(-0.5));
184 new TestCase( SECTION,
189 new TestCase( SECTION,
194 new TestCase( SECTION,