long foo(long);
long bar(long*, long);

long muh[] = {1, 3};
long kuh[] = {2,6};

RET(foo(1) == 20 && foo(0) == 5 && bar(muh, 5) == 5 && muh[0] == 5 && bar(muh,10) == 10 && muh[0] == 10 );