// Then sorts the elements according to the collected
// key values and the selected ordering
- Sort (0, indexes.Length - 1);
- }
-
- int CompareItems (int first_index, int second_index)
- {
- return context.Compare (first_index, second_index);
- }
-
- // We look at the first, middle, and last items in the subarray.
- // Then we put the largest on the right side, the smallest on
- // the left side, and the median becomes our pivot.
- int MedianOfThree (int left, int right)
- {
- int center = (left + right) / 2;
- if (CompareItems (indexes [center], indexes [left]) < 0)
- Swap (left, center);
- if (CompareItems (indexes [right], indexes [left]) < 0)
- Swap (left, right);
- if (CompareItems (indexes [right], indexes [center]) < 0)
- Swap (center, right);
- Swap (center, right - 1);
- return indexes [right - 1];
- }
-
- void Sort (int left, int right)
- {
- if (left + 3 <= right) {
- int l = left, r = right - 1, pivot = MedianOfThree (left, right);
- while (true) {
- while (CompareItems (indexes [++l], pivot) < 0) { }
- while (CompareItems (indexes [--r], pivot) > 0) { }
- if (l < r)
- Swap (l, r);
- else
- break;
- }
-
- // Restore pivot
- Swap (l, right - 1);
- // Partition and sort
- Sort (left, l - 1);
- Sort (l + 1, right);
- } else
- // If there are three items in the subarray, insertion sort is better
- InsertionSort (left, right);
- }
-
- void InsertionSort (int left, int right)
- {
- for (int i = left + 1; i <= right; i++) {
- int j, tmp = indexes [i];
-
- for (j = i; j > left && CompareItems (tmp, indexes [j - 1]) < 0; j--)
- indexes [j] = indexes [j - 1];
-
- indexes [j] = tmp;
- }
- }
-
- void Swap (int left, int right)
- {
- int temp = indexes [right];
- indexes [right] = indexes [left];
- indexes [left] = temp;
+ Array.Sort<int> (indexes, context);
}
public static IEnumerable<TElement> Sort (IEnumerable<TElement> source, SortContext<TElement> context)
sorter.PerformSort ();
- for (int i = 0; i < sorter.indexes.Length; i++)
+ for (int i = 0; i < sorter.elements.Length; i++)
yield return sorter.elements [sorter.indexes [i]];
}
}