2 * This file is part of the libpayload project.
4 * Copyright (C) 2007 Uwe Hermann <uwe@hermann-uwe.de>
5 * Copyright (C) 2008 Advanced Micro Devices, Inc.
7 * Redistribution and use in source and binary forms, with or without
8 * modification, are permitted provided that the following conditions
10 * 1. Redistributions of source code must retain the above copyright
11 * notice, this list of conditions and the following disclaimer.
12 * 2. Redistributions in binary form must reproduce the above copyright
13 * notice, this list of conditions and the following disclaimer in the
14 * documentation and/or other materials provided with the distribution.
15 * 3. The name of the author may not be used to endorse or promote products
16 * derived from this software without specific prior written permission.
18 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
19 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
20 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
21 * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
22 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
23 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
24 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
25 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
26 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
27 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
31 #include <libpayload.h>
32 #include <arch/types.h>
35 * Calculate the length of a fixed-size string.
37 * @param str The input string.
38 * @param maxlen Return at most maxlen characters as length of the string.
39 * @return The length of the string, not including the final NUL character.
40 * The maximum length returned is maxlen.
42 size_t strnlen(const char *str, size_t maxlen)
46 /* NULL and empty strings have length 0. */
50 /* Loop until we find a NUL character, or maxlen is reached. */
51 while ((*str++ != '\0') && (len < maxlen))
58 * Calculate the length of a string.
60 * @param str The input string.
61 * @return The length of the string, not including the final NUL character.
63 size_t strlen(const char *str)
67 /* NULL and empty strings have length 0. */
71 /* Loop until we find a NUL character. */
72 while (*str++ != '\0')
79 * Compare two strings.
81 * @param s1 The first string.
82 * @param s2 The second string.
83 * @return Returns a value less than zero, if s1 is shorter than s2. Returns
84 * zero, if s1 equals s2. Returns a value greater than zero, if
85 * s1 is longer than s2.
87 int strcmp(const char *s1, const char *s2)
91 /* Set c1 == c2, so that we can enter the while loop. */
95 /* Compare characters until they differ, or one of the strings ends. */
97 /* Read the next character from each string. */
101 /* Return something negative (if s1 is shorter than s2), or
102 zero (if s1 equals s2). */
107 /* Return someting positive (if s1 is longer than s2), or zero (if s1
108 and s2 are equal). */
113 * Compare two strings with fixed length.
115 * @param s1 The first string.
116 * @param s2 The second string.
117 * @param maxlen Return at most maxlen characters as length of the string.
118 * @return A non-zero value if s1 and s2 differ, or zero if s1 equals s2.
120 int strncmp(const char *s1, const char *s2, int maxlen)
124 for (i = 0; i < maxlen; i++) {
126 return s1[i] - s2[i];
132 char *strncpy(char *d, const char *s, int n)
134 /* use +1 to get the null terminator */
136 int max = n > strlen(s) + 1 ? strlen(s) + 1 : n;
139 for(i = 0; i < max; i++)
145 char *strcpy(char *d, const char *s)
147 return strncpy(d, s, strlen(s));
150 char *strncat(char *d, const char *s, int n)
152 char *p = d + strlen(d);
153 int max = n > strlen(s) ? strlen(s) : n;
156 for(i = 0; i < max; i++)
163 char * strchr(const char *s, int c)
165 char *p = (char *) s;
167 for( ; *p != 0; p++) {
176 char *strdup(const char *s)
187 char *strstr(const char *h, const char *n)
193 for(i = 0; i <= hn - nn; i++)
194 if (!strcmp(&h[i], n))
195 return (char *) &h[i];