new cases for stuff I have been working on

[mono.git] / mono / benchmark / regalloc.cs

diff --git a/mono/benchmark/regalloc.cs b/mono/benchmark/regalloc.cs
new file mode 100644 (file)
index 0000000..d84753f
--- /dev/null
+++ b/mono/benchmark/regalloc.cs
@@ -0,0 +1,54 @@
+//
+// To do this test well, I think you need to move the int aX = 0...
+// lines down as far as possible. That way, the lifespan of the variables
+// is short, and they can go into registers.
+//
+
+class T {
+       static int Main ()
+       {
+               for (int r = 0; r < 50; r ++) {
+                       int a0 = 0, b0 = 0, c0 = 0, d0 = 0;
+                       int a1 = 0, b1 = 0, c1 = 0, d1 = 0;
+                       int a2 = 0, b2 = 0, c2 = 0, d2 = 0;
+                       int a3 = 0, b3 = 0, c3 = 0, d3 = 0;
+                       int a4 = 0, b4 = 0, c4 = 0, d4 = 0;
+                       
+                       int x = 0;
+                       
+                       for (int i = 0; i < 400000; i ++) a0 ++;
+                       for (int i = 0; i < 400000; i ++) b0 ++;
+                       for (int i = 0; i < 400000; i ++) c0 ++;
+                       for (int i = 0; i < 400000; i ++) d0 ++;
+                       x ^= a0 ^ b0 ^ c0 ^ d0;
+                       
+                       for (int i = 0; i < 400000; i ++) a1 ++;
+                       for (int i = 0; i < 400000; i ++) b1 ++;
+                       for (int i = 0; i < 400000; i ++) c1 ++;
+                       for (int i = 0; i < 400000; i ++) d1 ++;
+                       x ^= a1 ^ b1 ^ c1 ^ d1;
+                       
+                       for (int i = 0; i < 400000; i ++) a2 ++;
+                       for (int i = 0; i < 400000; i ++) b2 ++;
+                       for (int i = 0; i < 400000; i ++) c2 ++;
+                       for (int i = 0; i < 400000; i ++) d2 ++;
+                       x ^= a2 ^ b2 ^ c2 ^ d2;
+                       
+                       for (int i = 0; i < 400000; i ++) a3 ++;
+                       for (int i = 0; i < 400000; i ++) b3 ++;
+                       for (int i = 0; i < 400000; i ++) c3 ++;
+                       for (int i = 0; i < 400000; i ++) d3 ++;
+                       x ^= a3 ^ b3 ^ c3 ^ d3;
+                       
+                       for (int i = 0; i < 400000; i ++) a4 ++;
+                       for (int i = 0; i < 400000; i ++) b4 ++;
+                       for (int i = 0; i < 400000; i ++) c4 ++;
+                       for (int i = 0; i < 400000; i ++) d4 ++;
+                       x ^= a4 ^ b4 ^ c4 ^ d4;
+                       
+                       if (x != 0)
+                               return 1;
+               }
+               return 0;
+       }
+}
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